Base | Representation |
---|---|
bin | 1010010001111011010111… |
… | …1111001011101111100001 |
3 | 1111000120022022201121001112 |
4 | 2210132311333023233201 |
5 | 2440142233210220131 |
6 | 40012324505513105 |
7 | 2244423441264632 |
oct | 244366577135741 |
9 | 44016268647045 |
10 | 11303112195041 |
11 | 3668694187427 |
12 | 13267514a2795 |
13 | 63cb56c5a694 |
14 | 2b1105b67889 |
15 | 1490471c002b |
hex | a47b5fcbbe1 |
11303112195041 has 2 divisors, whose sum is σ = 11303112195042. Its totient is φ = 11303112195040.
The previous prime is 11303112194923. The next prime is 11303112195077. The reversal of 11303112195041 is 14059121130311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10823251196641 + 479860998400 = 3289871^2 + 692720^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11303112195041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11303112194989 and 11303112195007.
It is not a weakly prime, because it can be changed into another prime (11303112135041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651556097520 + 5651556097521.
It is an arithmetic number, because the mean of its divisors is an integer number (5651556097521).
Almost surely, 211303112195041 is an apocalyptic number.
It is an amenable number.
11303112195041 is a deficient number, since it is larger than the sum of its proper divisors (1).
11303112195041 is an equidigital number, since it uses as much as digits as its factorization.
11303112195041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 32.
The spelling of 11303112195041 in words is "eleven trillion, three hundred three billion, one hundred twelve million, one hundred ninety-five thousand, forty-one".
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