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11303112210113 = 109411125224587
BaseRepresentation
bin1010010001111011010111…
…1111001111011011000001
31111000120022022202100201202
42210132311333033123001
52440142233211210423
640012324510110545
72244423441356603
oct244366577173301
944016268670652
1011303112210113
113668694197789
1213267514ab455
1363cb56c644b9
142b1105b6d173
151490471c4728
hexa47b5fcf6c1

11303112210113 has 8 divisors (see below), whose sum is σ = 11409585644160. Its totient is φ = 11196689233680.

The previous prime is 11303112210109. The next prime is 11303112210157. The reversal of 11303112210113 is 31101221130311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11303112210113 - 22 = 11303112210109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11303912210113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12164195 + ... + 13060392.

It is an arithmetic number, because the mean of its divisors is an integer number (1426198205520).

Almost surely, 211303112210113 is an apocalyptic number.

It is an amenable number.

11303112210113 is a deficient number, since it is larger than the sum of its proper divisors (106473434047).

11303112210113 is a wasteful number, since it uses less digits than its factorization.

11303112210113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25228807.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 11303112210113 its reverse (31101221130311), we get a palindrome (42404333340424).

The spelling of 11303112210113 in words is "eleven trillion, three hundred three billion, one hundred twelve million, two hundred ten thousand, one hundred thirteen".

Divisors: 1 109 4111 448099 25224587 2749479983 103698277157 11303112210113