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113031201300000 = 253557919932393
BaseRepresentation
bin11001101100110100100000…
…100110100001111000100000
3112211012200021202120022201220
4121230310200212201320200
5104303400400013100000
61040221452251255040
732544143352454104
oct3154644046417040
9484180252508656
10113031201300000
1133019299464415
121081625474a480
134b0ba48024549
141dcaa4ca2d904
15d103032761a0
hex66cd209a1e20

113031201300000 has 576 divisors, whose sum is σ = 375899775874560. Its totient is φ = 29732751360000.

The previous prime is 113031201299999. The next prime is 113031201300019. The reversal of 113031201300000 is 3102130311.

It is a super-2 number, since 2×1130312013000002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 47234098804 + ... + 47234101196.

It is an arithmetic number, because the mean of its divisors is an integer number (652603777560).

Almost surely, 2113031201300000 is an apocalyptic number.

113031201300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113031201300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (187949887937280).

113031201300000 is an abundant number, since it is smaller than the sum of its proper divisors (262868574574560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113031201300000 is an equidigital number, since it uses as much as digits as its factorization.

113031201300000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4503 (or 4475 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 113031201300000 its reverse (3102130311), we get a palindrome (113034303430311).

The spelling of 113031201300000 in words is "one hundred thirteen trillion, thirty-one billion, two hundred one million, three hundred thousand".