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11303132114 = 25651566057
BaseRepresentation
bin10101000011011100…
…00001101111010010
31002011201211121022202
422201232001233102
5141122100211424
65105333203202
7550050015641
oct124156015722
932151747282
1011303132114
1148803614aa
122235490502
1310b1980c71
1479325b358
154624bb2ae
hex2a1b81bd2

11303132114 has 4 divisors (see below), whose sum is σ = 16954698174. Its totient is φ = 5651566056.

The previous prime is 11303132111. The next prime is 11303132123. The reversal of 11303132114 is 41123130311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41123130311 = 333112345581.

It can be written as a sum of positive squares in only one way, i.e., 8804631889 + 2498500225 = 93833^2 + 49985^2 .

It is not an unprimeable number, because it can be changed into a prime (11303132111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2825783027 + ... + 2825783030.

Almost surely, 211303132114 is an apocalyptic number.

11303132114 is a deficient number, since it is larger than the sum of its proper divisors (5651566060).

11303132114 is an equidigital number, since it uses as much as digits as its factorization.

11303132114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5651566059.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11303132114 its reverse (41123130311), we get a palindrome (52426262425).

The spelling of 11303132114 in words is "eleven billion, three hundred three million, one hundred thirty-two thousand, one hundred fourteen".

Divisors: 1 2 5651566057 11303132114