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1130315353 = 2887391519
BaseRepresentation
bin100001101011111…
…0011111001011001
32220202212222011121
41003113303321121
54303330042403
6304054325241
740003344016
oct10327637131
92822788147
101130315353
11530040722
12276659821
1315023636b
14aa19070d
15693733bd
hex435f3e59

1130315353 has 4 divisors (see below), whose sum is σ = 1130709760. Its totient is φ = 1129920948.

The previous prime is 1130315327. The next prime is 1130315357. The reversal of 1130315353 is 3535130311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1130315353 is a prime.

It is a super-2 number, since 2×11303153532 = 2555225594455029218, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1130315357) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 192873 + ... + 198646.

It is an arithmetic number, because the mean of its divisors is an integer number (282677440).

Almost surely, 21130315353 is an apocalyptic number.

It is an amenable number.

1130315353 is a deficient number, since it is larger than the sum of its proper divisors (394407).

1130315353 is an equidigital number, since it uses as much as digits as its factorization.

1130315353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 394406.

The product of its (nonzero) digits is 2025, while the sum is 25.

The square root of 1130315353 is about 33620.1628937160. The cubic root of 1130315353 is about 1041.6773207771.

Adding to 1130315353 its reverse (3535130311), we get a palindrome (4665445664).

The spelling of 1130315353 in words is "one billion, one hundred thirty million, three hundred fifteen thousand, three hundred fifty-three".

Divisors: 1 2887 391519 1130315353