Base | Representation |
---|---|
bin | 1010010001111011101100… |
… | …1110111100100011110001 |
3 | 1111000120112110100101022120 |
4 | 2210132323032330203301 |
5 | 2440142423223310413 |
6 | 40012341332224453 |
7 | 2244425560364505 |
oct | 244367316744361 |
9 | 44016473311276 |
10 | 11303200213233 |
11 | 3668729934835 |
12 | 1326776a6b129 |
13 | 63cb6c267556 |
14 | 2b111371a305 |
15 | 14904eca9723 |
hex | a47bb3bc8f1 |
11303200213233 has 4 divisors (see below), whose sum is σ = 15070933617648. Its totient is φ = 7535466808820.
The previous prime is 11303200213231. The next prime is 11303200213267. The reversal of 11303200213233 is 33231200230311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11303200213233 - 21 = 11303200213231 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11303200213231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1883866702203 + ... + 1883866702208.
It is an arithmetic number, because the mean of its divisors is an integer number (3767733404412).
Almost surely, 211303200213233 is an apocalyptic number.
It is an amenable number.
11303200213233 is a deficient number, since it is larger than the sum of its proper divisors (3767733404415).
11303200213233 is an equidigital number, since it uses as much as digits as its factorization.
11303200213233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3767733404414.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 11303200213233 its reverse (33231200230311), we get a palindrome (44534400443544).
The spelling of 11303200213233 in words is "eleven trillion, three hundred three billion, two hundred million, two hundred thirteen thousand, two hundred thirty-three".
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