11303453131 has 2 divisors, whose sum is σ = 11303453132. Its totient is φ = 11303453130.

The previous prime is 11303453123. The next prime is 11303453159. The reversal of 11303453131 is 13135430311.

It is a weak prime.

It is an emirp because it is prime and its reverse (13135430311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11303453131 - 2³ = 11303453123 is a prime.

It is a super-2 number, since 2×11303453131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11303453096 and 11303453105.

It is not a weakly prime, because it can be changed into another prime (11303453101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651726565 + 5651726566.

It is an arithmetic number, because the mean of its divisors is an integer number (5651726566).

Almost surely, 2^11303453131 is an apocalyptic number.

11303453131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11303453131 is an equidigital number, since it uses as much as digits as its factorization.

11303453131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 11303453131 its reverse (13135430311), we get a palindrome (24438883442).

The spelling of 11303453131 in words is "eleven billion, three hundred three million, four hundred fifty-three thousand, one hundred thirty-one".