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113039981657 is a prime number
BaseRepresentation
bin110100101000110110…
…1010011110001011001
3101210202221200001020022
41221101231103301121
53323001213403112
6123532503040225
711111143663511
oct1512155236131
9353687601208
10113039981657
1143a38139349
1219aa8a40075
13a87626c815
145684c36841
152e18e37d72
hex1a51b53c59

113039981657 has 2 divisors, whose sum is σ = 113039981658. Its totient is φ = 113039981656.

The previous prime is 113039981609. The next prime is 113039981693. The reversal of 113039981657 is 756189930311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111329662921 + 1710318736 = 333661^2 + 41356^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113039981657 is a prime.

It is a super-3 number, since 3×1130399816573 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113039981599 and 113039981608.

It is not a weakly prime, because it can be changed into another prime (113039984657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56519990828 + 56519990829.

It is an arithmetic number, because the mean of its divisors is an integer number (56519990829).

Almost surely, 2113039981657 is an apocalyptic number.

It is an amenable number.

113039981657 is a deficient number, since it is larger than the sum of its proper divisors (1).

113039981657 is an equidigital number, since it uses as much as digits as its factorization.

113039981657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1224720, while the sum is 53.

The spelling of 113039981657 in words is "one hundred thirteen billion, thirty-nine million, nine hundred eighty-one thousand, six hundred fifty-seven".