11304048113 has 2 divisors, whose sum is σ = 11304048114. Its totient is φ = 11304048112.

The previous prime is 11304048083. The next prime is 11304048167. The reversal of 11304048113 is 31184040311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8944808929 + 2359239184 = 94577^2 + 48572^2 .

It is a cyclic number.

It is not a de Polignac number, because 11304048113 - 2¹⁴ = 11304031729 is a prime.

It is a super-3 number, since 3×11304048113³ (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11304048013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652024056 + 5652024057.

It is an arithmetic number, because the mean of its divisors is an integer number (5652024057).

Almost surely, 2^11304048113 is an apocalyptic number.

It is an amenable number.

11304048113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11304048113 is an equidigital number, since it uses as much as digits as its factorization.

11304048113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 11304048113 its reverse (31184040311), we get a palindrome (42488088424).

The spelling of 11304048113 in words is "eleven billion, three hundred four million, forty-eight thousand, one hundred thirteen".