Base | Representation |
---|---|
bin | 10101000011100101… |
… | …11101001010010001 |
3 | 1002011211021020120101 |
4 | 22201302331022101 |
5 | 141122413032311 |
6 | 5105421012401 |
7 | 550064006416 |
oct | 124162751221 |
9 | 32154236511 |
10 | 11304424081 |
11 | 4881064145 |
12 | 22359b4101 |
13 | 10b2014042 |
14 | 7934b610d |
15 | 462673ec1 |
hex | 2a1cbd291 |
11304424081 has 2 divisors, whose sum is σ = 11304424082. Its totient is φ = 11304424080.
The previous prime is 11304424039. The next prime is 11304424099. The reversal of 11304424081 is 18042440311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11300753025 + 3671056 = 106305^2 + 1916^2 .
It is a cyclic number.
It is not a de Polignac number, because 11304424081 - 217 = 11304293009 is a prime.
It is a super-3 number, since 3×113044240813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11304421081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652212040 + 5652212041.
It is an arithmetic number, because the mean of its divisors is an integer number (5652212041).
Almost surely, 211304424081 is an apocalyptic number.
It is an amenable number.
11304424081 is a deficient number, since it is larger than the sum of its proper divisors (1).
11304424081 is an equidigital number, since it uses as much as digits as its factorization.
11304424081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 11304424081 its reverse (18042440311), we get a palindrome (29346864392).
The spelling of 11304424081 in words is "eleven billion, three hundred four million, four hundred twenty-four thousand, eighty-one".
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