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113044304034 = 2326280239113
BaseRepresentation
bin110100101000111110…
…1110011000010100010
3101210210020210122102100
41221101331303002202
53323003320212114
6123533135431230
711111225505264
oct1512175630242
9353706718370
10113044304034
1143a3a620862
1219aaa385516
13a87712403c
14568563db34
152e194dd909
hex1a51f730a2

113044304034 has 12 divisors (see below), whose sum is σ = 244929325446. Its totient is φ = 37681434672.

The previous prime is 113044304017. The next prime is 113044304053. The reversal of 113044304034 is 430403440311.

It can be written as a sum of positive squares in only one way, i.e., 85645778409 + 27398525625 = 292653^2 + 165525^2 .

It is a super-3 number, since 3×1130443040343 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113044303989 and 113044304007.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3140119539 + ... + 3140119574.

Almost surely, 2113044304034 is an apocalyptic number.

113044304034 is an abundant number, since it is smaller than the sum of its proper divisors (131885021412).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113044304034 is a wasteful number, since it uses less digits than its factorization.

113044304034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6280239121 (or 6280239118 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 113044304034 its reverse (430403440311), we get a palindrome (543447744345).

The spelling of 113044304034 in words is "one hundred thirteen billion, forty-four million, three hundred four thousand, thirty-four".

Divisors: 1 2 3 6 9 18 6280239113 12560478226 18840717339 37681434678 56522152017 113044304034