Base | Representation |
---|---|
bin | 10101000011100110… |
… | …00011110101110010 |
3 | 1002011211022122002202 |
4 | 22201303003311302 |
5 | 141122414421232 |
6 | 5105421343202 |
7 | 550064152244 |
oct | 124163036562 |
9 | 32154278082 |
10 | 11304451442 |
11 | 4881082759 |
12 | 2235a07b02 |
13 | 10b202362b |
14 | 7934c2094 |
15 | 46267c162 |
hex | 2a1cc3d72 |
11304451442 has 16 divisors (see below), whose sum is σ = 17067359232. Its totient is φ = 5615368320.
The previous prime is 11304451441. The next prime is 11304451463. The reversal of 11304451442 is 24415440311.
11304451442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×113044514423 (a number of 31 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11304451441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 697058 + ... + 713090.
It is an arithmetic number, because the mean of its divisors is an integer number (1066709952).
Almost surely, 211304451442 is an apocalyptic number.
11304451442 is a deficient number, since it is larger than the sum of its proper divisors (5762907790).
11304451442 is a wasteful number, since it uses less digits than its factorization.
11304451442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18313.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 11304451442 its reverse (24415440311), we get a palindrome (35719891753).
The spelling of 11304451442 in words is "eleven billion, three hundred four million, four hundred fifty-one thousand, four hundred forty-two".
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