Base | Representation |
---|---|
bin | 1010010010001001110101… |
… | …1100010100110110010001 |
3 | 1111000221022221121101121111 |
4 | 2210202131130110312101 |
5 | 2440223211303341114 |
6 | 40014210103453321 |
7 | 2244621612606553 |
oct | 244423534246621 |
9 | 44027287541544 |
10 | 11306995371409 |
11 | 366a2a71292a1 |
12 | 1327455a57241 |
13 | 6403255c7b8a |
14 | 2b139378b4d3 |
15 | 1491c306abc4 |
hex | a489d714d91 |
11306995371409 has 2 divisors, whose sum is σ = 11306995371410. Its totient is φ = 11306995371408.
The previous prime is 11306995371401. The next prime is 11306995371437. The reversal of 11306995371409 is 90417359960311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6695466753600 + 4611528617809 = 2587560^2 + 2147447^2 .
It is a cyclic number.
It is not a de Polignac number, because 11306995371409 - 23 = 11306995371401 is a prime.
It is not a weakly prime, because it can be changed into another prime (11306995371401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5653497685704 + 5653497685705.
It is an arithmetic number, because the mean of its divisors is an integer number (5653497685705).
Almost surely, 211306995371409 is an apocalyptic number.
It is an amenable number.
11306995371409 is a deficient number, since it is larger than the sum of its proper divisors (1).
11306995371409 is an equidigital number, since it uses as much as digits as its factorization.
11306995371409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5511240, while the sum is 58.
The spelling of 11306995371409 in words is "eleven trillion, three hundred six billion, nine hundred ninety-five million, three hundred seventy-one thousand, four hundred nine".
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