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11306995371409 is a prime number
BaseRepresentation
bin1010010010001001110101…
…1100010100110110010001
31111000221022221121101121111
42210202131130110312101
52440223211303341114
640014210103453321
72244621612606553
oct244423534246621
944027287541544
1011306995371409
11366a2a71292a1
121327455a57241
136403255c7b8a
142b139378b4d3
151491c306abc4
hexa489d714d91

11306995371409 has 2 divisors, whose sum is σ = 11306995371410. Its totient is φ = 11306995371408.

The previous prime is 11306995371401. The next prime is 11306995371437. The reversal of 11306995371409 is 90417359960311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6695466753600 + 4611528617809 = 2587560^2 + 2147447^2 .

It is a cyclic number.

It is not a de Polignac number, because 11306995371409 - 23 = 11306995371401 is a prime.

It is not a weakly prime, because it can be changed into another prime (11306995371401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5653497685704 + 5653497685705.

It is an arithmetic number, because the mean of its divisors is an integer number (5653497685705).

Almost surely, 211306995371409 is an apocalyptic number.

It is an amenable number.

11306995371409 is a deficient number, since it is larger than the sum of its proper divisors (1).

11306995371409 is an equidigital number, since it uses as much as digits as its factorization.

11306995371409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5511240, while the sum is 58.

The spelling of 11306995371409 in words is "eleven trillion, three hundred six billion, nine hundred ninety-five million, three hundred seventy-one thousand, four hundred nine".