Base | Representation |
---|---|
bin | 1010010010001001110101… |
… | …1100010110010010101011 |
3 | 1111000221022221121200201112 |
4 | 2210202131130112102223 |
5 | 2440223211304033243 |
6 | 40014210103540535 |
7 | 2244621612633032 |
oct | 244423534262253 |
9 | 44027287550645 |
10 | 11306995377323 |
11 | 366a2a7132788 |
12 | 1327455a5a74b |
13 | 6403255ca789 |
14 | 2b139378d719 |
15 | 1491c306c818 |
hex | a489d7164ab |
11306995377323 has 2 divisors, whose sum is σ = 11306995377324. Its totient is φ = 11306995377322.
The previous prime is 11306995377319. The next prime is 11306995377343. The reversal of 11306995377323 is 32377359960311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11306995377323 - 22 = 11306995377319 is a prime.
It is a super-3 number, since 3×113069953773233 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11306995377343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5653497688661 + 5653497688662.
It is an arithmetic number, because the mean of its divisors is an integer number (5653497688662).
Almost surely, 211306995377323 is an apocalyptic number.
11306995377323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11306995377323 is an equidigital number, since it uses as much as digits as its factorization.
11306995377323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19289340, while the sum is 59.
The spelling of 11306995377323 in words is "eleven trillion, three hundred six billion, nine hundred ninety-five million, three hundred seventy-seven thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •