Base | Representation |
---|---|
bin | 10000011101000100011… |
… | …000011110011001001011 |
3 | 11000002121002001200112011 |
4 | 100131010120132121023 |
5 | 122011210224243413 |
6 | 2223240340200351 |
7 | 144456246401206 |
oct | 20350430363113 |
9 | 4002532050464 |
10 | 1130723665483 |
11 | 3a65a0038675 |
12 | 1631850990b7 |
13 | 8281c0773a9 |
14 | 3ca27a8a93d |
15 | 1e62cdc433d |
hex | 1074461e64b |
1130723665483 has 2 divisors, whose sum is σ = 1130723665484. Its totient is φ = 1130723665482.
The previous prime is 1130723665439. The next prime is 1130723665541. The reversal of 1130723665483 is 3845663270311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1130723665483 is a prime.
It is a super-2 number, since 2×11307236654832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1130723665403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565361832741 + 565361832742.
It is an arithmetic number, because the mean of its divisors is an integer number (565361832742).
Almost surely, 21130723665483 is an apocalyptic number.
1130723665483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130723665483 is an equidigital number, since it uses as much as digits as its factorization.
1130723665483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2177280, while the sum is 49.
The spelling of 1130723665483 in words is "one trillion, one hundred thirty billion, seven hundred twenty-three million, six hundred sixty-five thousand, four hundred eighty-three".
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