11310014314 has 4 divisors (see below), whose sum is σ = 16965021474. Its totient is φ = 5655007156.

The previous prime is 11310014299. The next prime is 11310014329. The reversal of 11310014314 is 41341001311.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (11310014299) and next prime (11310014329).

It can be written as a sum of positive squares in only one way, i.e., 6850045225 + 4459969089 = 82765^2 + 66783^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11310014291 and 11310014300.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2827503577 + ... + 2827503580.

Almost surely, 2^11310014314 is an apocalyptic number.

11310014314 is a deficient number, since it is larger than the sum of its proper divisors (5655007160).

11310014314 is an equidigital number, since it uses as much as digits as its factorization.

11310014314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5655007159.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11310014314 its reverse (41341001311), we get a palindrome (52651015625).

The spelling of 11310014314 in words is "eleven billion, three hundred ten million, fourteen thousand, three hundred fourteen".