1131003113321 has 4 divisors (see below), whose sum is σ = 1131402340692. Its totient is φ = 1130603885952.

The previous prime is 1131003113297. The next prime is 1131003113333. The reversal of 1131003113321 is 1233113001311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 440184479296 + 690818634025 = 663464^2 + 831155^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131003113321 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131003113293 and 1131003113302.

It is not an unprimeable number, because it can be changed into a prime (1131003115321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 199609436 + ... + 199615101.

It is an arithmetic number, because the mean of its divisors is an integer number (282850585173).

Almost surely, 2^{1131003113321} is an apocalyptic number.

It is an amenable number.

1131003113321 is a deficient number, since it is larger than the sum of its proper divisors (399227371).

1131003113321 is an equidigital number, since it uses as much as digits as its factorization.

1131003113321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 399227370.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1131003113321 its reverse (1233113001311), we get a palindrome (2364116114632).

The spelling of 1131003113321 in words is "one trillion, one hundred thirty-one billion, three million, one hundred thirteen thousand, three hundred twenty-one".