113101102113 has 4 divisors (see below), whose sum is σ = 150801469488. Its totient is φ = 75400734740.

The previous prime is 113101102111. The next prime is 113101102133. The reversal of 113101102113 is 311201101311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113101102113 - 2¹ = 113101102111 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 113101102092 and 113101102101.

It is not an unprimeable number, because it can be changed into a prime (113101102111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18850183683 + ... + 18850183688.

It is an arithmetic number, because the mean of its divisors is an integer number (37700367372).

Almost surely, 2^113101102113 is an apocalyptic number.

It is an amenable number.

113101102113 is a deficient number, since it is larger than the sum of its proper divisors (37700367375).

113101102113 is an equidigital number, since it uses as much as digits as its factorization.

113101102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37700367374.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 113101102113 its reverse (311201101311), we get a palindrome (424302203424).

The spelling of 113101102113 in words is "one hundred thirteen billion, one hundred one million, one hundred two thousand, one hundred thirteen".