Base | Representation |
---|---|
bin | 10101000100010001… |
… | …01010000110110011 |
3 | 1002012012222021120121 |
4 | 22202020222012303 |
5 | 141130342110303 |
6 | 5110142551111 |
7 | 550163242654 |
oct | 124210520663 |
9 | 32165867517 |
10 | 11310113203 |
11 | 488429a4a4 |
12 | 2237898497 |
13 | 10b325669c |
14 | 79415752b |
15 | 462de99bd |
hex | 2a222a1b3 |
11310113203 has 2 divisors, whose sum is σ = 11310113204. Its totient is φ = 11310113202.
The previous prime is 11310113197. The next prime is 11310113231. The reversal of 11310113203 is 30231101311.
It is a weak prime.
It is an emirp because it is prime and its reverse (30231101311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11310113203 - 213 = 11310105011 is a prime.
It is not a weakly prime, because it can be changed into another prime (11310113233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655056601 + 5655056602.
It is an arithmetic number, because the mean of its divisors is an integer number (5655056602).
Almost surely, 211310113203 is an apocalyptic number.
11310113203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310113203 is an equidigital number, since it uses as much as digits as its factorization.
11310113203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11310113203 its reverse (30231101311), we get a palindrome (41541214514).
The spelling of 11310113203 in words is "eleven billion, three hundred ten million, one hundred thirteen thousand, two hundred three".
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