Base | Representation |
---|---|
bin | 10101000100010001… |
… | …11111010100111011 |
3 | 1002012020010200210212 |
4 | 22202020333110323 |
5 | 141130402400443 |
6 | 5110144501335 |
7 | 550164054245 |
oct | 124210772473 |
9 | 32166120725 |
10 | 11310200123 |
11 | 4884349832 |
12 | 223791a84b |
13 | 10b3287111 |
14 | 79417b095 |
15 | 462e15618 |
hex | 2a223f53b |
11310200123 has 2 divisors, whose sum is σ = 11310200124. Its totient is φ = 11310200122.
The previous prime is 11310200101. The next prime is 11310200141. The reversal of 11310200123 is 32100201311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11310200123 - 214 = 11310183739 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11310200098 and 11310200107.
It is not a weakly prime, because it can be changed into another prime (11310200423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655100061 + 5655100062.
It is an arithmetic number, because the mean of its divisors is an integer number (5655100062).
Almost surely, 211310200123 is an apocalyptic number.
11310200123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310200123 is an equidigital number, since it uses as much as digits as its factorization.
11310200123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 11310200123 its reverse (32100201311), we get a palindrome (43410401434).
The spelling of 11310200123 in words is "eleven billion, three hundred ten million, two hundred thousand, one hundred twenty-three".
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