Base | Representation |
---|---|
bin | 10000011101010110000… |
… | …111100001011010001001 |
3 | 11000010100210221120121121 |
4 | 100131112013201122021 |
5 | 122012312412230043 |
6 | 2223330045435241 |
7 | 144466521446512 |
oct | 20352607413211 |
9 | 4003323846547 |
10 | 1131021211273 |
11 | 3a6732a96188 |
12 | 16324886bb21 |
13 | 828688c60a5 |
14 | 3ca553c1a09 |
15 | 1e64909aded |
hex | 107561e1689 |
1131021211273 has 2 divisors, whose sum is σ = 1131021211274. Its totient is φ = 1131021211272.
The previous prime is 1131021211219. The next prime is 1131021211297. The reversal of 1131021211273 is 3721121201311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 981215056969 + 149806154304 = 990563^2 + 387048^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131021211273 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131021211213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565510605636 + 565510605637.
It is an arithmetic number, because the mean of its divisors is an integer number (565510605637).
Almost surely, 21131021211273 is an apocalyptic number.
It is an amenable number.
1131021211273 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131021211273 is an equidigital number, since it uses as much as digits as its factorization.
1131021211273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 1131021211273 its reverse (3721121201311), we get a palindrome (4852142412584).
The spelling of 1131021211273 in words is "one trillion, one hundred thirty-one billion, twenty-one million, two hundred eleven thousand, two hundred seventy-three".
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