1131021330001 has 4 divisors (see below), whose sum is σ = 1131034577904. Its totient is φ = 1131008082100.

The previous prime is 1131021329981. The next prime is 1131021330011. The reversal of 1131021330001 is 1000331201311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1131021330001 - 2⁹ = 1131021329489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131021330011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6495055 + ... + 6666916.

It is an arithmetic number, because the mean of its divisors is an integer number (282758644476).

Almost surely, 2^{1131021330001} is an apocalyptic number.

It is an amenable number.

1131021330001 is a deficient number, since it is larger than the sum of its proper divisors (13247903).

1131021330001 is an equidigital number, since it uses as much as digits as its factorization.

1131021330001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13247902.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1131021330001 its reverse (1000331201311), we get a palindrome (2131352531312).

The spelling of 1131021330001 in words is "one trillion, one hundred thirty-one billion, twenty-one million, three hundred thirty thousand, one".