1131023113027 has 2 divisors, whose sum is σ = 1131023113028. Its totient is φ = 1131023113026.

The previous prime is 1131023113013. The next prime is 1131023113039. The reversal of 1131023113027 is 7203113201311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131023113027 is a prime.

It is a super-4 number, since 4×1131023113027⁴ (a number of 49 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131023112992 and 1131023113010.

It is not a weakly prime, because it can be changed into another prime (1131023113327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565511556513 + 565511556514.

It is an arithmetic number, because the mean of its divisors is an integer number (565511556514).

Almost surely, 2^{1131023113027} is an apocalyptic number.

1131023113027 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131023113027 is an equidigital number, since it uses as much as digits as its factorization.

1131023113027 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 1131023113027 its reverse (7203113201311), we get a palindrome (8334136314338).

The spelling of 1131023113027 in words is "one trillion, one hundred thirty-one billion, twenty-three million, one hundred thirteen thousand, twenty-seven".