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11310310113 = 329312867247
BaseRepresentation
bin10101000100010010…
…11010001011100001
31002012020100021200120
422202021122023201
5141130414410423
65110151110453
7550165023024
oct124211321341
932166307616
1011310310113
114884414433
122237972429
1310b32c51bb
147941a91bb
15462e37ee3
hex2a225a2e1

11310310113 has 8 divisors (see below), whose sum is σ = 15131883648. Its totient is φ = 7514471664.

The previous prime is 11310310111. The next prime is 11310310129. The reversal of 11310310113 is 31101301311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11310310113 - 21 = 11310310111 is a prime.

It is a super-2 number, since 2×113103101132 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11310310092 and 11310310101.

It is not an unprimeable number, because it can be changed into a prime (11310310111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6432745 + ... + 6434502.

It is an arithmetic number, because the mean of its divisors is an integer number (1891485456).

Almost surely, 211310310113 is an apocalyptic number.

It is an amenable number.

11310310113 is a deficient number, since it is larger than the sum of its proper divisors (3821573535).

11310310113 is a wasteful number, since it uses less digits than its factorization.

11310310113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12867543.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 11310310113 its reverse (31101301311), we get a palindrome (42411611424).

The spelling of 11310310113 in words is "eleven billion, three hundred ten million, three hundred ten thousand, one hundred thirteen".

Divisors: 1 3 293 879 12867247 38601741 3770103371 11310310113