Base | Representation |
---|---|
bin | 10000011101010110110… |
… | …101110000001000110111 |
3 | 11000010101122202021200220 |
4 | 100131112311300020313 |
5 | 122012324013031411 |
6 | 2223331201305423 |
7 | 144500026452660 |
oct | 20352665601067 |
9 | 4003348667626 |
10 | 1131033330231 |
11 | 3a6739913352 |
12 | 163250935273 |
13 | 8286b27a27c |
14 | 3ca56c58367 |
15 | 1e64a191b06 |
hex | 10756d70237 |
1131033330231 has 16 divisors (see below), whose sum is σ = 1723784204544. Its totient is φ = 646190443584.
The previous prime is 1131033330221. The next prime is 1131033330253. The reversal of 1131033330231 is 1320333301311.
It is not a de Polignac number, because 1131033330231 - 217 = 1131033199159 is a prime.
It is a super-2 number, since 2×11310333302312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131033330221) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4641565 + ... + 4879158.
It is an arithmetic number, because the mean of its divisors is an integer number (107736512784).
Almost surely, 21131033330231 is an apocalyptic number.
1131033330231 is a deficient number, since it is larger than the sum of its proper divisors (592750874313).
1131033330231 is an equidigital number, since it uses as much as digits as its factorization.
1131033330231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9526390.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 1131033330231 its reverse (1320333301311), we get a palindrome (2451366631542).
The spelling of 1131033330231 in words is "one trillion, one hundred thirty-one billion, thirty-three million, three hundred thirty thousand, two hundred thirty-one".
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