113103502531 has 2 divisors, whose sum is σ = 113103502532. Its totient is φ = 113103502530.

The previous prime is 113103502493. The next prime is 113103502541. The reversal of 113103502531 is 135205301311.

It is a strong prime.

It is an emirp because it is prime and its reverse (135205301311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113103502531 - 2²⁵ = 113069948099 is a prime.

It is a super-2 number, since 2×113103502531² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113103502496 and 113103502505.

It is not a weakly prime, because it can be changed into another prime (113103502541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56551751265 + 56551751266.

It is an arithmetic number, because the mean of its divisors is an integer number (56551751266).

Almost surely, 2^113103502531 is an apocalyptic number.

113103502531 is a deficient number, since it is larger than the sum of its proper divisors (1).

113103502531 is an equidigital number, since it uses as much as digits as its factorization.

113103502531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 113103502531 its reverse (135205301311), we get a palindrome (248308803842).

The spelling of 113103502531 in words is "one hundred thirteen billion, one hundred three million, five hundred two thousand, five hundred thirty-one".