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113104231340099 = 177497363721663
BaseRepresentation
bin11001101101111000100001…
…100010000001100001000011
3112211110122210100110202012212
4121231320201202001201003
5104311044431210340344
61040315211102412335
732552340201532646
oct3155704142014103
9484418710422185
10113104231340099
1133047264a7445a
12108284362910ab
134b158b614071c
141dd03b9c2ba5d
15d121798b179e
hex66de21881843

113104231340099 has 4 divisors (see below), whose sum is σ = 113104296836736. Its totient is φ = 113104165843464.

The previous prime is 113104231340069. The next prime is 113104231340119. The reversal of 113104231340099 is 990043132401311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113104231340099 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113104231340069) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30085859 + ... + 33635804.

It is an arithmetic number, because the mean of its divisors is an integer number (28276074209184).

Almost surely, 2113104231340099 is an apocalyptic number.

113104231340099 is a deficient number, since it is larger than the sum of its proper divisors (65496637).

113104231340099 is an equidigital number, since it uses as much as digits as its factorization.

113104231340099 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65496636.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 113104231340099 in words is "one hundred thirteen trillion, one hundred four billion, two hundred thirty-one million, three hundred forty thousand, ninety-nine".

Divisors: 1 1774973 63721663 113104231340099