Base | Representation |
---|---|
bin | 10000011101010111011… |
… | …110100010110000100011 |
3 | 11000010102101212112212122 |
4 | 100131113132202300203 |
5 | 122012334232221311 |
6 | 2223332222414455 |
7 | 144500216400125 |
oct | 20352736426043 |
9 | 4003371775778 |
10 | 1131044023331 |
11 | 3a6744957222 |
12 | 16325443142b |
13 | 82870552451 |
14 | 3ca5843d215 |
15 | 1e64b0a50db |
hex | 107577a2c23 |
1131044023331 has 2 divisors, whose sum is σ = 1131044023332. Its totient is φ = 1131044023330.
The previous prime is 1131044023327. The next prime is 1131044023349. The reversal of 1131044023331 is 1333204401311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1131044023331 - 22 = 1131044023327 is a prime.
It is a super-2 number, since 2×11310440233312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1131044023331.
It is not a weakly prime, because it can be changed into another prime (1131044023301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565522011665 + 565522011666.
It is an arithmetic number, because the mean of its divisors is an integer number (565522011666).
Almost surely, 21131044023331 is an apocalyptic number.
1131044023331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131044023331 is an equidigital number, since it uses as much as digits as its factorization.
1131044023331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 1131044023331 its reverse (1333204401311), we get a palindrome (2464248424642).
The spelling of 1131044023331 in words is "one trillion, one hundred thirty-one billion, forty-four million, twenty-three thousand, three hundred thirty-one".
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