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11311004442121 is a prime number
BaseRepresentation
bin1010010010011000110001…
…1001101101111000001001
31111001022200100101021201221
42210212030121231320021
52440304414114121441
640020112000042041
72245123143262426
oct244461431557011
944038610337657
1011311004442121
113670a7414847a
121328194603321
13640814074177
142b1653dc2d4d
15149359ed38d1
hexa498c66de09

11311004442121 has 2 divisors, whose sum is σ = 11311004442122. Its totient is φ = 11311004442120.

The previous prime is 11311004442079. The next prime is 11311004442161. The reversal of 11311004442121 is 12124440011311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11230300154896 + 80704287225 = 3351164^2 + 284085^2 .

It is a cyclic number.

It is not a de Polignac number, because 11311004442121 - 233 = 11302414507529 is a prime.

It is not a weakly prime, because it can be changed into another prime (11311004442161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655502221060 + 5655502221061.

It is an arithmetic number, because the mean of its divisors is an integer number (5655502221061).

Almost surely, 211311004442121 is an apocalyptic number.

It is an amenable number.

11311004442121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311004442121 is an equidigital number, since it uses as much as digits as its factorization.

11311004442121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 11311004442121 its reverse (12124440011311), we get a palindrome (23435444453432).

The spelling of 11311004442121 in words is "eleven trillion, three hundred eleven billion, four million, four hundred forty-two thousand, one hundred twenty-one".