113110122113233 has 4 divisors (see below), whose sum is σ = 129268710986560. Its totient is φ = 96951533239908.

The previous prime is 113110122113201. The next prime is 113110122113243. The reversal of 113110122113233 is 332311221011311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113110122113233 - 2⁵ = 113110122113201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113110122113198 and 113110122113207.

It is not an unprimeable number, because it can be changed into a prime (113110122113243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8079294436653 + ... + 8079294436666.

It is an arithmetic number, because the mean of its divisors is an integer number (32317177746640).

Almost surely, 2^{113110122113233} is an apocalyptic number.

It is an amenable number.

113110122113233 is a deficient number, since it is larger than the sum of its proper divisors (16158588873327).

113110122113233 is an equidigital number, since it uses as much as digits as its factorization.

113110122113233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16158588873326.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 113110122113233 its reverse (332311221011311), we get a palindrome (445421343124544).

The spelling of 113110122113233 in words is "one hundred thirteen trillion, one hundred ten billion, one hundred twenty-two million, one hundred thirteen thousand, two hundred thirty-three".