Base | Representation |
---|---|
bin | 110100101010111100… |
… | …1100011010111111001 |
3 | 101210221211222121002001 |
4 | 1221111321203113321 |
5 | 3323122214101103 |
6 | 123543454141001 |
7 | 11112656454634 |
oct | 1512571432771 |
9 | 353854877061 |
10 | 113110300153 |
11 | 43a738a7704 |
12 | 19b084b1761 |
13 | a8879c02b6 |
14 | 56902dcc1b |
15 | 2e201c801d |
hex | 1a55e635f9 |
113110300153 has 2 divisors, whose sum is σ = 113110300154. Its totient is φ = 113110300152.
The previous prime is 113110300123. The next prime is 113110300271. The reversal of 113110300153 is 351003011311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92681886969 + 20428413184 = 304437^2 + 142928^2 .
It is a cyclic number.
It is not a de Polignac number, because 113110300153 - 213 = 113110291961 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 113110300153.
It is not a weakly prime, because it can be changed into another prime (113110300123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555150076 + 56555150077.
It is an arithmetic number, because the mean of its divisors is an integer number (56555150077).
Almost surely, 2113110300153 is an apocalyptic number.
It is an amenable number.
113110300153 is a deficient number, since it is larger than the sum of its proper divisors (1).
113110300153 is an equidigital number, since it uses as much as digits as its factorization.
113110300153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135, while the sum is 19.
Adding to 113110300153 its reverse (351003011311), we get a palindrome (464113311464).
The spelling of 113110300153 in words is "one hundred thirteen billion, one hundred ten million, three hundred thousand, one hundred fifty-three".
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