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113110300153 is a prime number
BaseRepresentation
bin110100101010111100…
…1100011010111111001
3101210221211222121002001
41221111321203113321
53323122214101103
6123543454141001
711112656454634
oct1512571432771
9353854877061
10113110300153
1143a738a7704
1219b084b1761
13a8879c02b6
1456902dcc1b
152e201c801d
hex1a55e635f9

113110300153 has 2 divisors, whose sum is σ = 113110300154. Its totient is φ = 113110300152.

The previous prime is 113110300123. The next prime is 113110300271. The reversal of 113110300153 is 351003011311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92681886969 + 20428413184 = 304437^2 + 142928^2 .

It is a cyclic number.

It is not a de Polignac number, because 113110300153 - 213 = 113110291961 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113110300153.

It is not a weakly prime, because it can be changed into another prime (113110300123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555150076 + 56555150077.

It is an arithmetic number, because the mean of its divisors is an integer number (56555150077).

Almost surely, 2113110300153 is an apocalyptic number.

It is an amenable number.

113110300153 is a deficient number, since it is larger than the sum of its proper divisors (1).

113110300153 is an equidigital number, since it uses as much as digits as its factorization.

113110300153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 19.

Adding to 113110300153 its reverse (351003011311), we get a palindrome (464113311464).

The spelling of 113110300153 in words is "one hundred thirteen billion, one hundred ten million, three hundred thousand, one hundred fifty-three".