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11311101311113 is a prime number
BaseRepresentation
bin1010010010011001001000…
…1011001111100010001001
31111001022221002122202000101
42210212102023033202021
52440310113413423423
640020125340205401
72245125430534342
oct244462213174211
944038832582011
1011311101311113
1136710138a059a
121328200b39861
1364082b15c7b6
142b1662bdb0c9
1514936376a7ad
hexa49922cf889

11311101311113 has 2 divisors, whose sum is σ = 11311101311114. Its totient is φ = 11311101311112.

The previous prime is 11311101311089. The next prime is 11311101311129. The reversal of 11311101311113 is 31111310111311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11227679697529 + 83421613584 = 3350773^2 + 288828^2 .

It is a cyclic number.

It is not a de Polignac number, because 11311101311113 - 29 = 11311101310601 is a prime.

It is not a weakly prime, because it can be changed into another prime (11311131311113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655550655556 + 5655550655557.

It is an arithmetic number, because the mean of its divisors is an integer number (5655550655557).

Almost surely, 211311101311113 is an apocalyptic number.

It is an amenable number.

11311101311113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311101311113 is an equidigital number, since it uses as much as digits as its factorization.

11311101311113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 19.

Adding to 11311101311113 its reverse (31111310111311), we get a palindrome (42422411422424).

The spelling of 11311101311113 in words is "eleven trillion, three hundred eleven billion, one hundred one million, three hundred eleven thousand, one hundred thirteen".