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11311101312307 is a prime number
BaseRepresentation
bin1010010010011001001000…
…1011001111110100110011
31111001022221002122210122121
42210212102023033310303
52440310113413443212
640020125340215111
72245125430540666
oct244462213176463
944038832583577
1011311101312307
1136710138a1485
121328200b3a497
1364082b1601c4
142b1662bdb6dd
1514936376ad07
hexa49922cfd33

11311101312307 has 2 divisors, whose sum is σ = 11311101312308. Its totient is φ = 11311101312306.

The previous prime is 11311101312293. The next prime is 11311101312377. The reversal of 11311101312307 is 70321310111311.

11311101312307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11311101312307 - 215 = 11311101279539 is a prime.

It is not a weakly prime, because it can be changed into another prime (11311101312377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655550656153 + 5655550656154.

It is an arithmetic number, because the mean of its divisors is an integer number (5655550656154).

Almost surely, 211311101312307 is an apocalyptic number.

11311101312307 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311101312307 is an equidigital number, since it uses as much as digits as its factorization.

11311101312307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378, while the sum is 25.

Adding to 11311101312307 its reverse (70321310111311), we get a palindrome (81632411423618).

The spelling of 11311101312307 in words is "eleven trillion, three hundred eleven billion, one hundred one million, three hundred twelve thousand, three hundred seven".