Base | Representation |
---|---|
bin | 10000011101011011011… |
… | …110000010111111111011 |
3 | 11000010121001220102111001 |
4 | 100131123132002333323 |
5 | 122013003404031412 |
6 | 2223343014145431 |
7 | 144501661611412 |
oct | 20353336027773 |
9 | 4003531812431 |
10 | 1131111002107 |
11 | 3a6779744389 |
12 | 163272952277 |
13 | 828813a3a68 |
14 | 3ca632b6479 |
15 | 1e651dd5957 |
hex | 1075b782ffb |
1131111002107 has 2 divisors, whose sum is σ = 1131111002108. Its totient is φ = 1131111002106.
The previous prime is 1131111002011. The next prime is 1131111002123. The reversal of 1131111002107 is 7012001111311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131111002107 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131111002407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565555501053 + 565555501054.
It is an arithmetic number, because the mean of its divisors is an integer number (565555501054).
Almost surely, 21131111002107 is an apocalyptic number.
1131111002107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131111002107 is an equidigital number, since it uses as much as digits as its factorization.
1131111002107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42, while the sum is 19.
Adding to 1131111002107 its reverse (7012001111311), we get a palindrome (8143112113418).
The spelling of 1131111002107 in words is "one trillion, one hundred thirty-one billion, one hundred eleven million, two thousand, one hundred seven".
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