Base | Representation |
---|---|
bin | 10101000100011000… |
… | …11101011111011001 |
3 | 1002012021211221001220 |
4 | 22202030131133121 |
5 | 141131121010410 |
6 | 5110220202253 |
7 | 550204564251 |
oct | 124214353731 |
9 | 32167757056 |
10 | 11311110105 |
11 | 4884910489 |
12 | 2238099389 |
13 | 10b3515379 |
14 | 794336961 |
15 | 463045070 |
hex | 2a231d7d9 |
11311110105 has 16 divisors (see below), whose sum is σ = 18315823680. Its totient is φ = 5959909568.
The previous prime is 11311110043. The next prime is 11311110137. The reversal of 11311110105 is 50101111311.
It is a cyclic number.
It is not a de Polignac number, because 11311110105 - 27 = 11311109977 is a prime.
It is a super-2 number, since 2×113111101052 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4541370 + ... + 4543859.
It is an arithmetic number, because the mean of its divisors is an integer number (1144738980).
Almost surely, 211311110105 is an apocalyptic number.
11311110105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11311110105 is a deficient number, since it is larger than the sum of its proper divisors (7004713575).
11311110105 is an equidigital number, since it uses as much as digits as its factorization.
11311110105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9085320.
The product of its (nonzero) digits is 15, while the sum is 15.
Adding to 11311110105 its reverse (50101111311), we get a palindrome (61412221416).
The spelling of 11311110105 in words is "eleven billion, three hundred eleven million, one hundred ten thousand, one hundred five".
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