1131112132113 has 4 divisors (see below), whose sum is σ = 1508149509488. Its totient is φ = 754074754740.

The previous prime is 1131112132069. The next prime is 1131112132127. The reversal of 1131112132113 is 3112312111311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1131112132113 - 2⁶ = 1131112132049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1131112132113.

It is not an unprimeable number, because it can be changed into a prime (1131112132193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188518688683 + ... + 188518688688.

It is an arithmetic number, because the mean of its divisors is an integer number (377037377372).

Almost surely, 2^{1131112132113} is an apocalyptic number.

It is an amenable number.

1131112132113 is a deficient number, since it is larger than the sum of its proper divisors (377037377375).

1131112132113 is an equidigital number, since it uses as much as digits as its factorization.

1131112132113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377037377374.

The product of its digits is 108, while the sum is 21.

Adding to 1131112132113 its reverse (3112312111311), we get a palindrome (4243424243424).

The spelling of 1131112132113 in words is "one trillion, one hundred thirty-one billion, one hundred twelve million, one hundred thirty-two thousand, one hundred thirteen".