Base | Representation |
---|---|
bin | 11001101101111111110001… |
… | …010000010000100011011011 |
3 | 112211111101212112212020101020 |
4 | 121231333301100100203123 |
5 | 104311211344343430243 |
6 | 1040322535102253523 |
7 | 32553034041306543 |
oct | 3155776120204333 |
9 | 484441775766336 |
10 | 113112011311323 |
11 | 3304a597619a42 |
12 | 10829a478872a3 |
13 | 4b16555c05cab |
14 | 1dd09171bc323 |
15 | d124828e8283 |
hex | 66dff14108db |
113112011311323 has 16 divisors (see below), whose sum is σ = 154872557786496. Its totient is φ = 73392217859520.
The previous prime is 113112011311307. The next prime is 113112011311391. The reversal of 113112011311323 is 323113110211311.
It is not a de Polignac number, because 113112011311323 - 24 = 113112011311307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113112011311293 and 113112011311302.
It is not an unprimeable number, because it can be changed into a prime (113112011311393) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1560172465 + ... + 1560244962.
It is an arithmetic number, because the mean of its divisors is an integer number (9679534861656).
Almost surely, 2113112011311323 is an apocalyptic number.
113112011311323 is a deficient number, since it is larger than the sum of its proper divisors (41760546475173).
113112011311323 is a wasteful number, since it uses less digits than its factorization.
113112011311323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3120417754.
The product of its (nonzero) digits is 324, while the sum is 24.
Adding to 113112011311323 its reverse (323113110211311), we get a palindrome (436225121522634).
The spelling of 113112011311323 in words is "one hundred thirteen trillion, one hundred twelve billion, eleven million, three hundred eleven thousand, three hundred twenty-three".
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