Base | Representation |
---|---|
bin | 110100101011000000… |
… | …0000111010010011001 |
3 | 101210221222012222102120 |
4 | 1221112000013102121 |
5 | 3323123134120441 |
6 | 123543555051453 |
7 | 11113010210262 |
oct | 1512600072231 |
9 | 353858188376 |
10 | 113112020121 |
11 | 43a74871971 |
12 | 19b08ba0b89 |
13 | a888173129 |
14 | 5690629969 |
15 | 2e20417966 |
hex | 1a56007499 |
113112020121 has 4 divisors (see below), whose sum is σ = 150816026832. Its totient is φ = 75408013412.
The previous prime is 113112020113. The next prime is 113112020141. The reversal of 113112020121 is 121020211311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 113112020121 - 23 = 113112020113 is a prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 113112020121.
It is not an unprimeable number, because it can be changed into a prime (113112020101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18852003351 + ... + 18852003356.
It is an arithmetic number, because the mean of its divisors is an integer number (37704006708).
Almost surely, 2113112020121 is an apocalyptic number.
It is an amenable number.
113112020121 is a deficient number, since it is larger than the sum of its proper divisors (37704006711).
113112020121 is an equidigital number, since it uses as much as digits as its factorization.
113112020121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37704006710.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 113112020121 its reverse (121020211311), we get a palindrome (234132231432).
The spelling of 113112020121 in words is "one hundred thirteen billion, one hundred twelve million, twenty thousand, one hundred twenty-one".
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