Base | Representation |
---|---|
bin | 10101000100011001… |
… | …10110011110010001 |
3 | 1002012022001010102211 |
4 | 22202030312132101 |
5 | 141131132244213 |
6 | 5110222312121 |
7 | 550205501503 |
oct | 124214663621 |
9 | 32168033384 |
10 | 11311212433 |
11 | 4884980354 |
12 | 2238128641 |
13 | 10b354cb11 |
14 | 794361d73 |
15 | 46306553d |
hex | 2a2336791 |
11311212433 has 2 divisors, whose sum is σ = 11311212434. Its totient is φ = 11311212432.
The previous prime is 11311212379. The next prime is 11311212439. The reversal of 11311212433 is 33421211311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10962718209 + 348494224 = 104703^2 + 18668^2 .
It is a cyclic number.
It is not a de Polignac number, because 11311212433 - 29 = 11311211921 is a prime.
It is not a weakly prime, because it can be changed into another prime (11311212439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655606216 + 5655606217.
It is an arithmetic number, because the mean of its divisors is an integer number (5655606217).
Almost surely, 211311212433 is an apocalyptic number.
It is an amenable number.
11311212433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311212433 is an equidigital number, since it uses as much as digits as its factorization.
11311212433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 432, while the sum is 22.
Adding to 11311212433 its reverse (33421211311), we get a palindrome (44732423744).
The spelling of 11311212433 in words is "eleven billion, three hundred eleven million, two hundred twelve thousand, four hundred thirty-three".
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