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11311231023353 is a prime number
BaseRepresentation
bin1010010010011001100111…
…1010000011100011111001
31111001100021010201210202102
42210212121322003203321
52440310400120221403
640020150252313145
72245131564216212
oct244463172034371
944040233653672
1011311231023353
113671080036298
1213282384727b5
1364084bca72c1
142b1676124409
1514936ed3db88
hexa4999e838f9

11311231023353 has 2 divisors, whose sum is σ = 11311231023354. Its totient is φ = 11311231023352.

The previous prime is 11311231023341. The next prime is 11311231023371. The reversal of 11311231023353 is 35332013211311.

11311231023353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9635728597609 + 1675502425744 = 3104147^2 + 1294412^2 .

It is a cyclic number.

It is not a de Polignac number, because 11311231023353 - 28 = 11311231023097 is a prime.

It is not a weakly prime, because it can be changed into another prime (11311231023553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655615511676 + 5655615511677.

It is an arithmetic number, because the mean of its divisors is an integer number (5655615511677).

Almost surely, 211311231023353 is an apocalyptic number.

It is an amenable number.

11311231023353 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311231023353 is an equidigital number, since it uses as much as digits as its factorization.

11311231023353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860, while the sum is 29.

Adding to 11311231023353 its reverse (35332013211311), we get a palindrome (46643244234664).

The spelling of 11311231023353 in words is "eleven trillion, three hundred eleven billion, two hundred thirty-one million, twenty-three thousand, three hundred fifty-three".