Base | Representation |
---|---|
bin | 1010010010011001111000… |
… | …1101011100000100000001 |
3 | 1111001100110011120102202122 |
4 | 2210212132031130010001 |
5 | 2440311022110311223 |
6 | 40020201351454025 |
7 | 2245133431633445 |
oct | 244463615340401 |
9 | 44040404512678 |
10 | 11311303213313 |
11 | 3671107862714 |
12 | 1328258687315 |
13 | 640860c3185c |
14 | 2b1681956825 |
15 | 14937634d5c8 |
hex | a499e35c101 |
11311303213313 has 2 divisors, whose sum is σ = 11311303213314. Its totient is φ = 11311303213312.
The previous prime is 11311303213229. The next prime is 11311303213321. The reversal of 11311303213313 is 31331230311311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10577800036609 + 733503176704 = 3252353^2 + 856448^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11311303213313 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (11311303213333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655651606656 + 5655651606657.
It is an arithmetic number, because the mean of its divisors is an integer number (5655651606657).
Almost surely, 211311303213313 is an apocalyptic number.
It is an amenable number.
11311303213313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311303213313 is an equidigital number, since it uses as much as digits as its factorization.
11311303213313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 26.
Adding to 11311303213313 its reverse (31331230311311), we get a palindrome (42642533524624).
The spelling of 11311303213313 in words is "eleven trillion, three hundred eleven billion, three hundred three million, two hundred thirteen thousand, three hundred thirteen".
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