11311312000033 has 2 divisors, whose sum is σ = 11311312000034. Its totient is φ = 11311312000032.

The previous prime is 11311311999979. The next prime is 11311312000067. The reversal of 11311312000033 is 33000021311311.

11311312000033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9259404727329 + 2051907272704 = 3042927^2 + 1432448^2 .

It is a cyclic number.

It is not a de Polignac number, because 11311312000033 - 2³³ = 11302722065441 is a prime.

It is not a weakly prime, because it can be changed into another prime (11311312000333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655656000016 + 5655656000017.

It is an arithmetic number, because the mean of its divisors is an integer number (5655656000017).

Almost surely, 2^{11311312000033} is an apocalyptic number.

It is an amenable number.

11311312000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311312000033 is an equidigital number, since it uses as much as digits as its factorization.

11311312000033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11311312000033 its reverse (33000021311311), we get a palindrome (44311333311344).

The spelling of 11311312000033 in words is "eleven trillion, three hundred eleven billion, three hundred twelve million, thirty-three", and thus it is an aban number.