Base | Representation |
---|---|
bin | 10000011101011100101… |
… | …110111100101111010011 |
3 | 11000010122112210220102102 |
4 | 100131130232330233103 |
5 | 122013024321211011 |
6 | 2223345052511015 |
7 | 144502340101400 |
oct | 20353456745723 |
9 | 4003575726372 |
10 | 1131132210131 |
11 | 3a678a70a280 |
12 | 163279a7b46b |
13 | 828858baca1 |
14 | 3ca660372a7 |
15 | 1e653bc473b |
hex | 1075cbbcbd3 |
1131132210131 has 48 divisors (see below), whose sum is σ = 1471359103200. Its totient is φ = 859875878400.
The previous prime is 1131132210121. The next prime is 1131132210157. The reversal of 1131132210131 is 1310122311311.
It is not a de Polignac number, because 1131132210131 - 26 = 1131132210067 is a prime.
It is a super-2 number, since 2×11311322101312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1131132210121) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 37133195 + ... + 37163643.
It is an arithmetic number, because the mean of its divisors is an integer number (30653314650).
Almost surely, 21131132210131 is an apocalyptic number.
1131132210131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1131132210131 is a deficient number, since it is larger than the sum of its proper divisors (340226893069).
1131132210131 is an frugal number, since it uses more digits than its factorization.
1131132210131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30597 (or 30508 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1131132210131 its reverse (1310122311311), we get a palindrome (2441254521442).
The spelling of 1131132210131 in words is "one trillion, one hundred thirty-one billion, one hundred thirty-two million, two hundred ten thousand, one hundred thirty-one".
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