Base | Representation |
---|---|
bin | 10101000100011011… |
… | …00111010000010001 |
3 | 1002012022102021112010 |
4 | 22202031213100101 |
5 | 141131210142431 |
6 | 5110230453133 |
7 | 550210263153 |
oct | 124215472021 |
9 | 32168367463 |
10 | 11311412241 |
11 | 4884aa7488 |
12 | 22382041a9 |
13 | 10b35bca4c |
14 | 7943b4ad3 |
15 | 4630a4846 |
hex | 2a2367411 |
11311412241 has 4 divisors (see below), whose sum is σ = 15081882992. Its totient is φ = 7540941492.
The previous prime is 11311412227. The next prime is 11311412243. The reversal of 11311412241 is 14221411311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14221411311 = 3 ⋅4740470437.
It is not a de Polignac number, because 11311412241 - 222 = 11307217937 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11311412243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885235371 + ... + 1885235376.
It is an arithmetic number, because the mean of its divisors is an integer number (3770470748).
Almost surely, 211311412241 is an apocalyptic number.
It is an amenable number.
11311412241 is a deficient number, since it is larger than the sum of its proper divisors (3770470751).
11311412241 is an equidigital number, since it uses as much as digits as its factorization.
11311412241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3770470750.
The product of its digits is 192, while the sum is 21.
Adding to 11311412241 its reverse (14221411311), we get a palindrome (25532823552).
The spelling of 11311412241 in words is "eleven billion, three hundred eleven million, four hundred twelve thousand, two hundred forty-one".
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