Base | Representation |
---|---|
bin | 1010010010011100100001… |
… | …0110110011110100101010 |
3 | 1111001102021110002211012000 |
4 | 2210213020112303310222 |
5 | 2440313444120004002 |
6 | 40020355451231430 |
7 | 2245160106114540 |
oct | 244471026636452 |
9 | 44042243084160 |
10 | 11312010313002 |
11 | 367143aa11123 |
12 | 1328415448576 |
13 | 640944588639 |
14 | 2b170b81bd90 |
15 | 1493b847461c |
hex | a49c85b3d2a |
11312010313002 has 64 divisors (see below), whose sum is σ = 29719567353600. Its totient is φ = 3120554566080.
The previous prime is 11312010312917. The next prime is 11312010313013. The reversal of 11312010313002 is 20031301021311.
11312010313002 is a `hidden beast` number, since 1 + 131 + 201 + 0 + 31 + 300 + 2 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 515953749 + ... + 515975672.
It is an arithmetic number, because the mean of its divisors is an integer number (464368239900).
Almost surely, 211312010313002 is an apocalyptic number.
11312010313002 is an abundant number, since it is smaller than the sum of its proper divisors (18407557040598).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11312010313002 is a wasteful number, since it uses less digits than its factorization.
11312010313002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1031929468 (or 1031929462 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 11312010313002 its reverse (20031301021311), we get a palindrome (31343311334313).
The spelling of 11312010313002 in words is "eleven trillion, three hundred twelve billion, ten million, three hundred thirteen thousand, two".
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