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113121003300000 = 253553533832789
BaseRepresentation
bin11001101110001000001001…
…001101111110010010100000
3112211112021002012212120220220
4121232020021031332102200
5104311333303321100000
61040331023240003040
732553502626043143
oct3156101115762240
9484467065776826
10113121003300000
1133053391339143
121082b737160480
134b17359b0c957
141dd112b50a05a
15d1280c0411a0
hex66e20937e4a0

113121003300000 has 576 divisors, whose sum is σ = 373311586529280. Its totient is φ = 29990850560000.

The previous prime is 113121003299999. The next prime is 113121003300013. The reversal of 113121003300000 is 3300121311.

It is a super-2 number, since 2×1131210033000002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 40559698606 + ... + 40559701394.

It is an arithmetic number, because the mean of its divisors is an integer number (648110393280).

Almost surely, 2113121003300000 is an apocalyptic number.

113121003300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113121003300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (186655793264640).

113121003300000 is an abundant number, since it is smaller than the sum of its proper divisors (260190583229280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113121003300000 is an equidigital number, since it uses as much as digits as its factorization.

113121003300000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3563 (or 3535 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 113121003300000 its reverse (3300121311), we get a palindrome (113124303421311).

The spelling of 113121003300000 in words is "one hundred thirteen trillion, one hundred twenty-one billion, three million, three hundred thousand".