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11312112323033 is a prime number
BaseRepresentation
bin1010010010011100111001…
…1011111100100111011001
31111001102112120001110122022
42210213032123330213121
52440314201223314113
640020413533504225
72245162455151064
oct244471633744731
944042476043568
1011312112323033
113671492555835
121328443642075
1364095c753cc2
142b171b1b38db
151493c23c4908
hexa49ce6fc9d9

11312112323033 has 2 divisors, whose sum is σ = 11312112323034. Its totient is φ = 11312112323032.

The previous prime is 11312112322943. The next prime is 11312112323047. The reversal of 11312112323033 is 33032321121311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6307571974144 + 5004540348889 = 2511488^2 + 2237083^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11312112323033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11312112322993 and 11312112323011.

It is not a weakly prime, because it can be changed into another prime (11312112323233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656056161516 + 5656056161517.

It is an arithmetic number, because the mean of its divisors is an integer number (5656056161517).

Almost surely, 211312112323033 is an apocalyptic number.

It is an amenable number.

11312112323033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312112323033 is an equidigital number, since it uses as much as digits as its factorization.

11312112323033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 26.

Adding to 11312112323033 its reverse (33032321121311), we get a palindrome (44344433444344).

The spelling of 11312112323033 in words is "eleven trillion, three hundred twelve billion, one hundred twelve million, three hundred twenty-three thousand, thirty-three".