Base | Representation |
---|---|
bin | 1010010010011100111011… |
… | …1010011101010001101011 |
3 | 1111001102120010002210222011 |
4 | 2210213032322131101223 |
5 | 2440314210300234011 |
6 | 40020414421140351 |
7 | 2245162613142130 |
oct | 244471672352153 |
9 | 44042503083864 |
10 | 11312120321131 |
11 | 3671497018933 |
12 | 132844625a6b7 |
13 | 6409612c45c6 |
14 | 2b171c296587 |
15 | 1493c2e54621 |
hex | a49cee9d46b |
11312120321131 has 4 divisors (see below), whose sum is σ = 12928137509872. Its totient is φ = 9696103132392.
The previous prime is 11312120321113. The next prime is 11312120321143. The reversal of 11312120321131 is 13112302121311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11312120321131 is a prime.
It is a super-2 number, since 2×113121203211312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11312120321431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808008594360 + ... + 808008594373.
It is an arithmetic number, because the mean of its divisors is an integer number (3232034377468).
Almost surely, 211312120321131 is an apocalyptic number.
11312120321131 is a deficient number, since it is larger than the sum of its proper divisors (1616017188741).
11312120321131 is an equidigital number, since it uses as much as digits as its factorization.
11312120321131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1616017188740.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 11312120321131 its reverse (13112302121311), we get a palindrome (24424422442442).
The spelling of 11312120321131 in words is "eleven trillion, three hundred twelve billion, one hundred twenty million, three hundred twenty-one thousand, one hundred thirty-one".
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