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11312132131 = 67173975941
BaseRepresentation
bin10101000100100000…
…10111000000100011
31002012100202212000201
422202100113000203
5141131401212011
65110254130031
7550216352026
oct124220270043
932170685021
1011312132131
114885449333
1222384b0917
1310b37b2611
147945211bd
15463197cc1
hex2a2417023

11312132131 has 8 divisors (see below), whose sum is σ = 11547345744. Its totient is φ = 11078870880.

The previous prime is 11312132123. The next prime is 11312132179. The reversal of 11312132131 is 13123121311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11312132131 - 23 = 11312132123 is a prime.

It is a super-2 number, since 2×113121321312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11312132099 and 11312132108.

It is not an unprimeable number, because it can be changed into a prime (11312132191) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 476380 + ... + 499561.

It is an arithmetic number, because the mean of its divisors is an integer number (1443418218).

Almost surely, 211312132131 is an apocalyptic number.

11312132131 is a deficient number, since it is larger than the sum of its proper divisors (235213613).

11312132131 is an equidigital number, since it uses as much as digits as its factorization.

11312132131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 976181.

The product of its digits is 108, while the sum is 19.

Adding to 11312132131 its reverse (13123121311), we get a palindrome (24435253442).

The spelling of 11312132131 in words is "eleven billion, three hundred twelve million, one hundred thirty-two thousand, one hundred thirty-one".

Divisors: 1 67 173 11591 975941 65388047 168837793 11312132131