Search a number
-
+
1131222030217 is a prime number
BaseRepresentation
bin10000011101100010000…
…101100101011110001001
311000010212210211020102021
4100131202011211132021
5122013220314431332
62223402022004441
7144504510414466
oct20354205453611
94003783736367
101131222030217
113a6826388454
121632a3b76721
138289b3a9076
143ca73d3866d
151e65ba17c97
hex10762165789

1131222030217 has 2 divisors, whose sum is σ = 1131222030218. Its totient is φ = 1131222030216.

The previous prime is 1131222030209. The next prime is 1131222030283. The reversal of 1131222030217 is 7120302221311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 908750384656 + 222471645561 = 953284^2 + 471669^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131222030217 - 23 = 1131222030209 is a prime.

It is a super-2 number, since 2×11312220302172 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131222030191 and 1131222030200.

It is not a weakly prime, because it can be changed into another prime (1131222040217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565611015108 + 565611015109.

It is an arithmetic number, because the mean of its divisors is an integer number (565611015109).

Almost surely, 21131222030217 is an apocalyptic number.

It is an amenable number.

1131222030217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131222030217 is an equidigital number, since it uses as much as digits as its factorization.

1131222030217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 1131222030217 its reverse (7120302221311), we get a palindrome (8251524251528).

The spelling of 1131222030217 in words is "one trillion, one hundred thirty-one billion, two hundred twenty-two million, thirty thousand, two hundred seventeen".